sched/debug: Implement consistent task-state printing
Currently get_task_state() and task_state_to_char() report different
states, create a number of common helpers and unify the reported state
space.
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Cc: linux-kernel@vger.kernel.org
Signed-off-by: Ingo Molnar <mingo@kernel.org>
diff --git a/fs/proc/array.c b/fs/proc/array.c
index 525157c..01196d3a 100644
--- a/fs/proc/array.c
+++ b/fs/proc/array.c
@@ -130,19 +130,8 @@
static inline const char *get_task_state(struct task_struct *tsk)
{
- unsigned int state = (tsk->state | tsk->exit_state) & TASK_REPORT;
-
- /*
- * Parked tasks do not run; they sit in __kthread_parkme().
- * Without this check, we would report them as running, which is
- * clearly wrong, so we report them as sleeping instead.
- */
- if (tsk->state == TASK_PARKED)
- state = TASK_INTERRUPTIBLE;
-
- BUILD_BUG_ON(1 + ilog2(TASK_REPORT) != ARRAY_SIZE(task_state_array)-1);
-
- return task_state_array[fls(state)];
+ BUILD_BUG_ON(1 + ilog2(TASK_REPORT) != ARRAY_SIZE(task_state_array) - 1);
+ return task_state_array[__get_task_state(tsk)];
}
static inline int get_task_umask(struct task_struct *tsk)